Question

A force of 10N acts on a block of mass 10kg at an angle of 60° displaces it 5m. Calculate the work done. (cos 60°=1/2).​

Answer 1

Answer:

the answer will be 60 Joule

Answer 2

Given:

★Force Applied = 10N

☆Mass of Block = 10kg

★Angle made = 60° = 1/2

☆Displacement ( s ) = 5m

To Find:

➮Work Done

Formulae Used:

➮Work Done = FS Cosθ

Now,

➟ Work Done = F × s × cos 60°

➟ Work Done = 10 × 5 × 1/2

➟ Work Done = 25J

Hence, The work done by the force is 25J.

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