Question

A force of 10N acts on a body A of mass 2kg. What is its acceleration?

It then acts on another body B and produces an acceleration of 2.5ms^-2. Find the
mass of B. If this same force acts on the bodies A and B tied together, what would be the acceleration of the combined bodies?

Answer 1

Given:-

• Force Applied = 10N

• Mass of Body "A" = 2kg

• Acceleration of body "B" = 2.5m/s²

To Find:-

• The Acceleration produced on Object "A".

• The Mass of object "B"

• The Acceleration Produced by force in Combined bodies.

Formulae used

• F = ma.

Where,

F = force

m = mass

a = Acceleration.

Now,

For Body "A"

F = ma

10 = 2 × a

a = 10/2

a = 5m/s²

For Body "B"

F = ma

10 = m × 2.5

m = 10/2.5

m = 4kg

Now, Atq.

• if the two bodies A and B will be tied together then their masses will also be Combined

Hence,

F = ma

F = (m¹ + m²)a

12 = (2 + 4)a

12 = 6a

a = 12/6

a = 2m/s².

So, The accceleration Produced by force on Combined body is 2m/s².

Answer 2

★ Given :-

• Force (F) = 10 Newtons
• Mass of Body 'A' (m) = 2kg
• Acceleration of Body 'B' (a) = 2.5m/s²

★ To Find :-

• Acceleration produced on Body 'A'
• Mass of Body 'B'
• Acceleration produced by combining forces of Body 'A' & 'B'

★ Solution :-

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1)

We know Formula for force,

$✓ \: f = ma$

Placing Values,

$⟶10 = 2 \times a$

$⟶a = \frac{\cancel{10}}{\cancel{2}}$

$⟶a = 5 {m</strong><strong>/</strong><strong>s}^{2}$

⛬ Acceleration produced on Body 'B' is 5m/s²

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2)

We know Formula For Force,

$✓ \: f = ma$

Placing Values,

$⟶10 = m \times 2.5$

$⟶m = \frac{\cancel{10}}{\cancel{2.5}}$

$⟶m = 4kg$

⛬ Mass of body 'B' is 4kg

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3)

Formula for combined forces will become,

$✓ \: f = ( {m}^{1} ) + ( {m}^{2} ) \times a$

Placing Values,

$⟶12 = (2 + 4)a$

$⟶12 = 6a$

$⟶a = \frac{\cancel{12}}{\cancel{6}}$

$⟶a = 2 {m/s}^{2}$

⛬ Acceleration is 2m/s²

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