A force of 10N acts on a body of mass 2 kg for 3s, initially at rest. Calculate:
(i)the velocity acquired by the body
(ii)change in momentum of the body
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i) force= mass *acceleration
10=2*a
a=10/2=5m/s
a=v-u/t
5=v-0/3
5=v/3
v=5*3
v=15 m/s(ans)
ii) change in momentum = mv-mu=2*15-2*0=30-0= 30 kgm/s(ans)
10=2*a
a=10/2=5m/s
a=v-u/t
5=v-0/3
5=v/3
v=5*3
v=15 m/s(ans)
ii) change in momentum = mv-mu=2*15-2*0=30-0= 30 kgm/s(ans)
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