Question

A force of 10N acts on a body of mass 2 kg. If the body was initially at rest, calculate the velocity acquired by it in 5s.​

Answer 1

f=ma

a=f/m=10/2=5

v=u+at

v=5×5=25m/s

Answer 2

Explanation:

Force = mass × acceleration

F=10N

m=2kg

then,

a=

m

F

=

2

10

=5m/s

2

(i) Now,

u=0

t=3sec

v=u+at=0+3×5=15m/s

(ii)Initialmomentum=mu=2×0=0

Finalmomentum=mv=2×15=30kg−m/s

Change in momentum=Final momentum - Initial momentum

=30−0=30kg−m/s