Question

A force of 10n acts on a body of mass 2kg moving initially with a velocity of 4m/s. find the velocity attained by the body in 5 sec​...¿¿​

Answer 1

F= ma

10=2×a

10/2=a

5 = a

v=u+at

v= 4+5×5

v= 4+25

v= 29

please follow me

Answer 2

Force = mass × acceleration

F=10N

m=2kg

then,

a=

m

F

=

2

10

=5m/s

2

(i) Now,

u=0

t=3sec

v=u+at=0+3×5=15m/s

(ii)Initialmomentum=mu=2×0=0

Finalmomentum=mv=2×15=30kg−m/s

Change in momentum=Final momentum - Initial momentum

=30−0=30kg−m/s