A force of 10N acts up on body of mass 2kg for 3secondsFind the K.E acquired by the body in 3 seconds and 6seconds
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Answer:
Force=10 Newton
M of body=2 kg
T=3 Second
Initial velocity =0
So apply :-
F=ma
=10N=2kg×(v-u)/t
=10N=2kg×(v-u)/3sec
=30/2 =v
=15m/s =v
Now :-
K.E= 1/2mv²
=1/2×2kg×225
=225J
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