Question

A Force of 10N displaces a body by a distance of 2m at an angle 60° to its own direction. find the amount of work done.

● please give the answer!!

(class 9th) ​

Answer 1

$\huge\bf{\red{\underline{\underline{\mathcal{AnSwer}}}}}$

Given:-

• Force = 10N
• angle = 60⁰
• displacement = 2m

To find:-

• Amount of work done

Formula:-

$\underline\pink{\boxed{\bf Work = Force×displacement×CosØ}}$

Solution:-

• we know that Cos60⁰ = $\sf\dfrac{1}{2}$

:$\implies$$\sf Work = 10×2×\dfrac{1}{2}$

:$\implies$$\sf Work = 10 J$

Answer 2

Answer:-

$\pink{\bigstar}$ The amount of work done is $\large\leadsto\boxed{\tt\purple{10 \: J}}$

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• Given:-

• Force of 10 N displaces a body by a distance of 2m at angle of 60° to its own direction.

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• To Find:-

• Amount of work done = ?

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• Solution:-

We know,

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$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{W = Fs. cos \theta}}}$

where,

• W = Work done

• F = Force applied

• s = displacement

• cos θ = angle at which body is displaced

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• Substituting in the Formula:-

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➪ $\sf W = 10 \times 2 \times cos 60^{\circ}$

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➪ $\sf W = 20 \times cos 60^{\circ}$

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➪ $\sf W = 20 \times \dfrac{1}{2} \ \ \ \ \ \ \ \dashrightarrow\bf\pink{[\because cos \: 60^{\circ} = \dfrac{1}{2}]}$

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★ $\large{\bf\red{W = 10 \: J}}$

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✯ Note:- Unit of Work is Joules [J].

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Therefore, the work done is 10 J.