Question

A Force of 10N displaces a body by a distance of 2m at an angle 60° to its own direction. find the amount of work done.



plz anyone answer this question...​

Answer 1

Answer:

F=10N,S=2m,θ=60

0

So, Work=F×Scosθ=10×2cos60

0

=10×2×

2

1

=10J

Answer 2

Answer:

F= 10N

S= 2m

angle= 60

we knowthat

W = FScos (thetha)

= 10*2 cos(90-30)

$= 10 \times 2\sin(30)$

= 10J. ( sin 30= 1/2)

your answer 10J