A force of 10N displaces a body by a distance of 2m at an angle of 60° to it's own direction.Find the amount of work done. PLEASE ANSWER WITHOUT "COS" FORMULA. AND FOL LO W Me
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Force, F = 10 N
Angle with horizontal, θ = 60o
Displacement in horizontal direction, S = 2 m
Component of force along horizontal direction is = F cosθ = (10)(cos60) = 5 N
So, work done is, W = (5)(2) = 10 J
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