Question

a force of 10N holds an ideal spring with a 20N/m spring constant in compression.the potential energy stored in spring?

Answer 1

 Hi I have an answer for your question A force of 10N holds an ideal spring with a 20 N/m spring constant in compression the potential energy stored

 The compression of the spring is 0 . 5 m 

Energy stored = 1 / 2 . k . x ^ 2 = 0 . 5 . 20 . 0 . 5 ^ 2 = 2 . 5 J

Hope this answer helps you

Answer 2

Answer:

Potential energy stored in a spring =

1/2 kx^2

K =20

X= 10/20=0.5

Substitute

1/2 • 20•0.5 • 0.5 = 2.5

Hoppe it is helpful