Question

A Force of 10N is applied on a object of mass 1kg for 2s,which was initially at rest. What is the work done

Explain with appropriate equation

Answer 1

Answer:

20joules

U= initial velocity=0, since body is at rest and F=ma

a=F/m Therefore, a=10N/1kg = 1m/second-square

Now, using v=u+at, v=0 + 1.t Therefore, v=0 + (1x2)=2m/s

Therefore, W.D=FxD = 10N x 2m/s = 20 Joules