Question

a force of 10n is applied on a object of mass 5 kg for 5 sec . calculate 1.the impulse of the force 2. the change in momentum of object 3. the change in velocity of object 4.the acceleration of object​

Answer 1

Given :

Magnitude of applied force = 10N

Mass of body = 5kg

Time interval = 5s

To Find :

• Impulse
• Change in momentum
• Change in velocity
• Acceleration

Solution :

■ As per newton's second law of motion force is measured as the rate of change of linear momentum.

• F = ∆p/∆t = m (v - u) / t

F denotes force

dp denotes change in momentum

t denotes time

m denotes mass

v denotes final velocity

u denotes initial velocity

A] Impulse of the force :

We know that, Impulse (J) = F × dt

➠ J = F × dt

➠ J = 10 × 5

➠ J = 50 N s

B] Change in momentum :

As per second law of motion;

⭆ F = ∆p / ∆t

⭆ dp = F / ∆t = J

⭆ Change in momentum = 50 N s

C] Change in velocity :

⇒ ∆p = m × ∆v

⇒ 50 = 5 × ∆v

⇒ ∆v = 50/5

⇒ ∆v = 10 m/s

D] Acceleration of object :

We know that acceleration is defined as the rate of change of velocity$.$

➙ a = ∆v / ∆t

➙ a = 10/5

➙ a = 2 m/s²