Question

A force of 10N is making an angle of 30degree with horizontal .its horizontal component will be
1 point

Answer 1

$\sf \red{horizontal \: component \: is \: the \: force} \\ \sf \red{ \: that \: is \: applied \: as \: a \: result } \\ \sf \red{\: of \: the \: diagonal \: application \: of \: force.}$

$\sf{here \: in \: this \: case,} \\ \sf{given \: diagonal \: force =10N.} \\ \sf{angle= 30°} \\ \sf{ horizontal \: component \: is } \\ \sf{found using trigonometry..}$

$\sf{ѕo,} \\ \sf{A \: vector \: of \: magnitude \: 10 N \: is \: provided.} \\ \sf{It \: is \: at \: an \: angle \: of \: 30° \: to \: the \: + \: x axis.}$

$\sf{To \: find:} \\ \sf{The \: components } \\ \sf{along \: the \: x \: and \: y \: axis.} \\ \sf{Calculation:} \\ \sf{Along \: x \: axis:}$

$\sf \pink{F(x) = F cos(θ)} \\ \sf \pink{:⇒F(x) = 10 × cos(30)} \\ \sf \pink{:⇒F(x) = 10 (√3/2) = 5√3N}$

$\tt{Along \: \: \: y \: \: \: axis:}$

$\sf \purple{F(y) = F sin(θ)} \\ \sf \purple{:⇒ F(y) = 10 sin(30°)} \\ \sf \purple{:⇒ F(y) = 10 × ½} \\ \sf \purple{ :⇒F(y) = 5 N.}$

$\sf \orange{Additional \: information:} \\ \sf{1. A \: vector \: is \: a \: quantity \: that } \\ \sf{\: can \: be \: defined \: with \: both} \\ \sf{ \: magnitude \: and \: direction.} \\ \\ \sf{2. Since \: force \: is \: a \: vector,} \\ \sf{ \: we \: are \: able \: to \: break \: it \: down }\\ \sf{ \: into \: components \: along \: chosen \: axis.}$

Answer 2

$\huge\tt\colorbox{pink}{Qᴜᴇsᴛɪᴏɴ}$

❥ horizontal components the force

that is applied as a result

of the diagonal application of force.

$\begin{gathered} \sf{here \: in \: this \: case,} \\ \sf{given \: diagonal \: force =10N.} \\ \sf{angle= 30°} \\ \sf{ horizontal \: component \: is } \\ \sf{found using trigonometry..}\end{gathered}$

$\begin{gathered} \sf{ѕo,} \\ \sf{A \: vector \: of \: magnitude \: 10 N \: is \: provided.} \\ \sf{It \: is \: at \: an \: angle \: of \: 30° \: to \: the \: + \: x axis.}\end{gathered}$

$\begin{gathered} \sf{To \: find:} \\ \sf{The \: components } \\ \sf{along \: the \: x \: and \: y \: axis.} \\ \sf{Calculation:} \\ \sf{Along \: x \: axis:}\end{gathered}$

$\begin{gathered} \sf \pink{F(x) = F cos(θ)} \\ \sf \pink{:⇒F(x) = 10 × cos(30)} \\ \sf \pink{:⇒F(x) = 10 (√3/2) = 5√3N}\end{gathered}$

$\tt{Along \: \: \: y \: \: \: axis:}$

$\begin{gathered} \sf \purple{F(y) = F sin(θ)} \\ \sf \purple{:⇒ F(y) = 10 sin(30°)} \\ \sf \purple{:⇒ F(y) = 10 × ½} \\ \sf \purple{ :⇒F(y) = 5 N.} \end{gathered}$

$\begin{gathered} \sf \orange{Additional \: information:} \\ \sf{1. A \: vector \: is \: a \: quantity \: that } \\ \sf{\: can \: be \: defined \: with \: both} \\ \sf{ \: magnitude \: and \: direction.} \\ \\ \sf{2. Since \: force \: is \: a \: vector,} \\ \sf{ \: we \: are \: able \: to \: break \: it \: down }\\ \sf{ \: into \: components \: along \: chosen \: axis.}\end{gathered}$