Question

a force of 12 Newton starts acting on a body kept at rest find the momentum at 1 second two second and five seconds

Answer 1

Force = mass× acceleration

F =10 N

mass = 2 kg

a = F/m = 10/2 = 5 m/s²

i)now, u = 0

t = 3 sec

v = u + at = 0 + 3×5 = 15 m/s

ii) initial momentum = mu = 2×0 =0

final momentum = mv = 2×15 = 30 kg m/s

change in momentum = final momentum - initial momentum 

                                  = 30 -0 = 30 kg m/s

Answer 2

Hi there !

_______________________

We have ;

$\mathsf{F = \frac{ P_2 - P_1}{t_2 - t_1} }$

At t = 0, the momentum is $\mathsf {P_1}$ = 0.

So, at a time to, it's value is given by

$\mathsf{F = \frac{ P_2 - P_1}{t -0} }$

Or, $\mathsf{P_2 = P _1 + Ft = Ft}$

The momentum at t = 1 s is ;

$\mathsf{P_2 = Ft } \\ \\ \mathsf{P_2 = (12 \times 1) } \\ \\ \mathsf{P_2 = 12 \: N \: s}$

At t = 2s , it is

$\mathsf{P_2 = Ft } \\ \\ \mathsf{P_2 = (12 \times 2) } \\ \\ \mathsf{P_2 = 24 \: N \: s}$

At t = 5s , it is

$\mathsf{P_2 = Ft } \\ \\ \mathsf{P_2 = (12 \times 5) } \\ \\ \mathsf{P_2 = 60 \: N \: s}$

_______________________

Thanks for the question !

☺️❤️☺️