Question

a force of 12 Newton starts acting

on a body kept at rest find the momentum at 1 second two second and five seconds

Answer 1

Hi there !

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We have ;

$\mathsf{F = \frac{ P_2 - P_1}{t_2 - t_1} }$

At t = 0, the momentum is $\mathsf {P_1}$ = 0.

So, at a time to, it's value is given by

$\mathsf{F = \frac{ P_2 - P_1}{t -0} }$

Or, $\mathsf{P_2 = P _1 + Ft = Ft}$

The momentum at t = 1 s is ;

$\mathsf{P_2 = Ft } \\ \\ \mathsf{P_2 = (12 \times 1) } \\ \\ \mathsf{P_2 = 12 \: N \: s}$

At t = 2s , it is

$\mathsf{P_2 = Ft } \\ \\ \mathsf{P_2 = (12 \times 2) } \\ \\ \mathsf{P_2 = 24 \: N \: s}$

At t = 5s , it is

$\mathsf{P_2 = Ft } \\ \\ \mathsf{P_2 = (12 \times 5) } \\ \\ \mathsf{P_2 = 60 \: N \: s}$

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Answer 2

$\bf{Hello \: Friend \:!!!}$

$<font color ="red ">$Given :-

Force :- 12 N

We know that,

$= >f = \frac{p2 - p1}{t1 - t2}$
T =0,

Momentum 1 (P1) = 0

So 1 time is given.

Therefore,

$= > f = \frac{p2 - p1}{t - 0}$

The momentum is T = 1


P2 = Ft

P2 = 12 × 1

P2 = 12 N


At

T = 2 seconds

We know that,

P2 = Ft

P2 = 12 × 2

P2 = 24 N



At,

T = 5 seconds

We know that,

P2 = Ft

P2 = 12 × 5

P2 = 60 N



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Ansh as ans81