Question

A force of 120 N acts on the surface of area 5 cm square. What would be the pressure exerted on the surface? *​

Answer 1

Question ⤵️

A force of 120 N acts on the surface of area 5 cm square. What would be the pressure exerted on the surface?

Answer ⤵️

The thrust will be 1200N10 cm^2=10/10000=0. 001m^2pressure =thrust/ area1200/0. 001=1200*1000=1200000N