Question

A force of 120 N and a force of 20 N acting simultaneously at a point may produce a resultant force of:

Answer 1

Answer:

not sure about this answer

Answer 2

The Main Answer is: The resultant force can be 140N if forces are in the same direction; 100N if they are acting in the opposite direction; and it can be other values depending on the angle between the direction of the forces.

Given: 2 forces of 20N and 120N

To Find: Possible magnitudes of the resultant force

Solution:

According to the rule of Superposition of forces, the vector sum of 2 forces depends on the angle between them.

In this question, we have not been given any angle between the forces, so there can be an infinite number of different values of resultants for different measures of angles.

Resultant of forces = $\sqrt[]{A^{2} + B^{2} + 2ABcos\alpha }$  (where A and B are the magnitudes of forces and 'α' is the angle between them.

CASE 1-

For α = 0° -

Resultant = $\sqrt[]{A^{2} + B^{2} + 2AB }$ = $\sqrt[]{(A + B)^{2} }$ = A + B

Resultant = 120 + 20 = 140N

CASE 2-

For α = 180° -

Resultant = $\sqrt[]{A^{2} + B^{2} - 2AB }$ = $\sqrt[]{(A - B)^2 }$ = A - B

Resultant = 120 - 20 = 100N

CASE 3-

For α = 90° -

Resultant = $\sqrt[]{A^{2} + B^{2} + 2ABcos\(90 }$ = $\sqrt[]{A^{2} + B^{2} + 0 }$  

               = $\sqrt{120^2 + 20^2}$ = $\sqrt{14400 + 40}$

Resultant = √14440N

In this way, we can put in different values of α to obtain different values of the resultant vector.

Therefore, the value of the resultant force can be 140N, 100N, or √14440N depending on different values of the angle between them.

For a similar question on resultant forces, refer to:

https://brainly.in/question/23931428?msp_srt_exp=6

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