Physics, asked by ashvikamalik, 6 months ago

A force of 1200 N acts on the surface of area 10 m2 normally. What would be the thrust and pressure on the surface respectively?

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
42

Answer

  • Pressure will be 120 Pascal

Explanation

Given

  • Force Applied = 1200 N
  • Area = 10 m²

To Find

  • The pressure on the surface

Solution

  • Pressure is equal to the force divided by the area
  • SI unit if pressure is Pascal (P)
  • The lesser the area more will be the pressure a d more the area lesser will be the pressure
  • This is why they sharpen a knife befor it used so that we can reduce the area of constant and hence increase the cutting ability

Pressure applied

→ Pressure = Force/Area

→ Pressure = 12000/10

→ Pressure = 120 Pa

Note : Here the thrust was directly given on the question a d is equal to 1200 N. Thrust and Force are the same

Answered by Anonymous
45

Given :-

Force acting on the surface = 1200 N

Area of the surface = 10 m²

To Find :-

The thrust and pressure on the surface respectively.

Solution :-

We know that,

  • t = Thrust
  • a = Area
  • f = Force

Thrust is the force acting normally to a surface.

Hence, Thrust (t) = 1200 N

By the formula,

\underline{\boxed{\sf Pressure= \dfrac{Thrust}{Area} }}

Given that,

Thrust (t) = 1200 N

Area = 10 m² =

Substituting their values,

p = 1200/10

p = 120 Pa

Therefore, the thrust and pressure on the surface is 1200 N and 120 Pa respectively.

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