A force of 1200 N compresses a spring from its natural length of 18 cm to a length of 16 cm. How much work is done in compressing it from 16 cm to 14 cm?
Answers
Answer:36 J
Explanation:
(2400+1200)÷2 ×0.02= 36 J
Answer:
Work done performed is -24joule (This work is done by external applied force not by the spring).
Explanation:
Provided that:
F = 1200 N force is applied to compress a spring from its natural length of 18 cm to 16 cm .
So, Initial length (L1) = 18 cm
Final length (L2) = 16 cm
From Hooke's law we know that:
F = -K (L1 - L2) ; where K is Spring Constant.
From equation (i) we can calculate the value of K for the given spring;
Now to compress the spring from 16 cm to 14 cm;
external force needed;
Work done to compress the spring from 16 cm to 14 cm;
So the Work done performed is -24 joule .
Negetive sign (-ve) indicates this work done is made by external force not by the system (Spring). And this work done is stored in the spring as Potential energy.