Question

A force of 1200 newton act on the surface of area 10cm2 normally what would be the thrust or pressure on the surface

Answer 1

Hey there!

Given,

Force(F) = 1200 N

Area (A) = 10 cm² = 0.001 m²

We know,

Thrust is the force acting normally to a surface.

So, Thrust = 1200 N

And, Pressure = Thrust / Area

                        = 1200 / 0.001

                       = 1200000 Pa

                       = 1.2 × 10⁶ Pa

Hope it Helps You!

Answer 2

Answer:

If a force of 1200 newton act on the surface of area 10 sq.cm, then the pressure on the surface = = 12,000,000 Pa

Explanation:

• Given: -

        Force acting on the area = 1200 N

        Area on which the force acts = 10 sq. cm

• To be calculated : -

        Pressure or thrust by the force on the area.

• Pressure is  " the physical force exerted on a surface." The force applied is perpendicular to surface of objects per unit area." S, the expression for pressure is: - P = F/ A   ----------------  (1)

        Where P = Pressure ( in Pascals or N/sq. m)

                    F = Force      ( in Newton (N) )

                    A = Area         ( in sq. m)

• Solution: -

       We, have the value of force and area, we have to put it in the     expression (1) to get the value of pressure.

     Force = 1200 N

    Area = 10 sq. cm

    Since area is in sq.cm, we'll have to convert it into sq. m. We'll divide 10 sq. cm by 10000 to get 0.0001 sq. m

    Pressure = F/ A

    Putting values in expression,

    P = 1200/ 0.0001

       = 12,000,000 Pa