Question

a force of 1200N acts on the surface of area 10cm2 normally .what would be the trust and pressure on the surface?

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Answer 1

Answer:-

Given:

Force (F) = 1200 N

Area (A) = 10 cm²

We have to find thrust & Pressure applied.

Thrust = Force

→ Thrust = 1200 N

Now,

Pressure = Force/Area

1 cm² = 1/10⁴ m²

→ 10 cm² = 10 * 1/10⁴ m²

→ 10 cm² = 10^(-3) m²

Hence,

→ P = (1200) / (1/10³)

→ P = 1200 * 10³

→ P = 12 * 10² * 10³

→ P = 12 * 10⁵ N/m²

Hence,

• Thrust = 1200 N
• Pressure = 12 * 10⁵ Pa.

Answer 2

Answer:

• Force = 1200 N
• Area = 10 cm²
• Thrust & Pressure = ?

↝ Thrust = Force = 1200 N

⠀

SI Unit of Pressure is Pascal (Newton per metre square), Area in Metre Square and Force in Newton.

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf Pressure=\dfrac{Force}{Area}\\\\\\:\implies\sf Pressure=\dfrac{1200\:N}{10\:cm^2}\\\\\\:\implies\sf Pressure=\dfrac{1200\:N}{10 \times \frac{1}{100 \times 100} \:m^2}\\\\\\:\implies\sf Pressure=\dfrac{1200\:N}{\frac{1}{10 \times 100} \:m^2}\\\\\\:\implies\sf Pressure=1200 \times 10 \times 100\:N\:m^{ - 2}\\\\\\:\implies\underline{\boxed{\sf Pressure = 12 \times 10^{5} \:Pascal}}$