Question

a force of 1200N is applied to car of mass 1000kg.if the co efficient friction is 0.03 the acceleration of the car

Answer 1

Mv^2/r(centripetal force)=frictional force*mg(normal reaction)

V^2/r=friction*g

V=✓friction*r*g

   =✓.64*20*10

   =8✓2

   =11.2(D)