Question

a force of 14 Newton acting on a body of mass 10 kg changes its velocity from 5 metre per second to 2 metre per second determine acceleration and time for which force acts and distance covered

Answer 1

acceleration is in negative 1.4m/ secsquare
and time for force act on body is 2.1s

Answer 2

Acceleration = Force / Mass
= - 14 N / (10 kg)
= - 1.4 m/s²
[Negative sign indicates that body is decelerating]

Time = (v - u) / Acceleration
= (2 m/s - 5 m/s) / (- 1.4 m/s²)
= 2.14 seconds

Distance = (v² - u²) / (2a)
= (2² - 5²) / (2 × (-1.4)) m
= 7.5 m