Question

a force of 15 Newton acts for 5 seconds on a body of mass 5 kg which is initially at rest calculate final velocity of the body and the displacement of the body

Answer 1

Given force = 50N
mass= 5kg

Force = mass × acceleration

Therefore a= 50/5
= 10m/s^2

Time is 5second

u,initial velocity =0

The forcula for v (final velocity) is
v =u+at
= 0+ 10(5)
=50m/s

Hope it helped

Answer 2

The final velocity of the body is 15m/s and displacement is 37.5 meters.

GIVEN

A force of 15 Newton acts for 5 seconds on a body of mass 5 kg which is initially at rest.

TO FIND

Final velocity of the body and displacement.

SOLUTION

We can simply solve the above problem as follows;

We know that,

The formula to calculate force is given as;

F = ma

Where,

F = force exerted

m = mass of the object

a = acceleration

Putting the values in the above problem as follows;

15 = 5 × a

a = 15/5 = 3 m/s²

Now,

Applying first equation of motion;

v = u+at

Where,

v = Final velocity

u = initial velocity = 0 (Body starts from rest)

a = acceleration = 3 m/s²

t = time = 5 seconds

Now,

v = 0 + 3 × 5

v = 15m/s

Applying third equation of motion to find the displacement of the body

v² = u² + 2as

15² = 0 + 2 × 3 × s

225 = 6s

s = 225/6 = 37.5 meters.

Hence, The final velocity of the body is 15m/s and displacement is 37.5 meters.

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