Question

A force of 150 N pushes a box. Starting from rest, the box achieves a velocity of 1.50 m⁄s in 2.5 s. Find the coefficient of sliding between the box and the floor.

Answer 1

mass is not known so answer can't be found out

Answer 2

Answer:

μk=0.06

Explanation:

Given:

Vo=0m/s (the object started from rest)

Vf=1.50m/s

t=2.5s

F=150N

g=9.81m/s²

Required: μk

Solution:

*Calculating mass first,

F=mA → m=F/A

using kinematics formula,

A=(Vf-Vo)/t

A=(1.50m/s-0m/s)/2.5s

A=0.6m/s²

Since F is given,

m = F/A

   = (150N)/0.6m/s²

m = 250kg

*Finally, calculating for μk

fk=μk*N

where: fk=F

F=μk*N

where: N=W and W=m*g

F=μk*m*g

*Extract μk from the formula

μk = F/mg

    = (150N)/[(250kg)(9.8m/s²)]

μk = 0.06

I hope this helps. Anyway, please verify it still. Good luck!