Question

A force of 1500 N acts on the surface of area 15 cm 2 normally. What would be the thrust and pressure on the surface?

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Answer 1

Answer:

given:

force: 1500N

perpendicular area: 15 cm^2 or 15/10000 m^2

pressure= perpendicular force/area in meter-square

p= 1500/(15/10000)

= 10^6 N/m^2

or 10^6 pascal.

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