Question

A force of 15n act for 5 second on a body of mass 5kg which is initial at rest calculate the final velocity on the body

Answer 1

Answer :-

v = 15m/s

Given:-

F = 15 N

t = 5s

m = 5 kg

u = 0m/s

To find :-

Final velocity (v) of the body.

Solution:-

From Newton 2 nd Law we have, the formula of force :-

★ $\boxed{\sf{F = m.a}}$

And from equation of motion we have :-

★ $\boxed{\sf{ a = \dfrac{v-u}{t}}}$

Now by joining this two formula we get,

★ $\boxed{\sf{F = m.\dfrac{v-u}{t}}}$

Now, put the given value,

→$15 = 5 \times \dfrac{v -0}{5}$

→$15 = 5 \times \dfrac{v}{5}$

→$15 = v$

→$v = 15m/s$

hence,

final velocity will be 15m/s.

Answer 2

${\mathfrak{\purple{\underline{\underline{Answer:-}}}}}$

$\sf{v = 15m/s}$

${\mathfrak{\purple{\underline{\underline{Explanation:-}}}}}$

★ Given:

u = 0 m/s.

t = 5s.

a = ?

v = ?

The acceleration produced in body of mass 5 kg by force of 15 N is given as,

$\sf{acceleration\;(a)=\dfrac{Force\;(F)}{Mass\;(m)}}$

★ ${\boxed{\boxed{\sf{a=\frac{15}{3} =3m/s^{2}}}}}$

For finding final velocity using first equation of motion, v = u + at.

$\sf{\implies v = u+at}$

$\sf{\implies v = 0+3\times 5}$

$\sf{\implies v=15m/s}$

★ ${\boxed{\boxed{\sf{v=15m/s}}}}$