Math, asked by harry5974, 6 months ago

A force of 15N acts for 5s on a body of mass 5kg which is initially at rest.Calculate.a)final velocity of the body.b)the displacement of the body​

Answers

Answered by vikram17458
9

Answer:

v = 15 m / sec

d = 75 m

Step-by-step explanation:

v = final velocity

u = initial velocity

initially body was at rest thats why u is taken 0

acceleration = (v - u)/t

a = (v - 0 ) / 5 = v/5

force = mass × acceleration

15. = 5 × a

15. = 5 × v/5

15. = v

d = v × t

d = 15 × 5 = 75 m

Answered by thapaavinitika6765
1

 \huge\boxed{\underline{answer}}

u =0

Mass = 5 kg

Force =15 N

Time =5s

v=?

Force = mass × acceleration

15 = 5 = acceleration

3 = acceleration

v= u+at

v=0+3(5)

v=15

-u²= 2as

(15)²-(0)²=2(3)s

225=6s

37.5= s

So, a) final velocity = 15 m/s

b) displacement = 37.5m

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