A force of 15n acts on area of 1m². the force kept the same but the area is reduced to half . what will happen to the pressure?
answer is pressure get doubled
how it is solved
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Answered by
2
Pressure= Force÷Area
In first case
Pressure= 15÷1= 15Pa
In second case
Area is reduced to half, so area is= 0.5m^2
Pressure =
= 30 Pa
Compare 30Pa and 15Pa, 30Pa is double of 15Pa
So Pressure is doubled when area is halved.
Answered by
2
pressure = force/area
p(1)=15n/1m²
=15pascal
p(2)=15n/0.5m²
= (15n*2)/(0.5m²*2).... multipling both the denominator and numerator by 2
=30n/1m²
= 30pascal
proved p(2) is double of p(1).
plz mark it as brainliest answer
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