Physics, asked by poojadobhal35486, 24 days ago

A force of 15N is applied at a distance of 40 cm from the point of pivot. Calculate the moment of force about the point of pivot​

Answers

Answered by shobhadevikunnu
1

Answer:

6Nm

Explanation:

F=15N

perpendicular distance=0.4m

Torque or moment of force=F×perpendicular distance

=15×0.4

=6Nm

Answered by Yazhini16
0

Answer:

Hi brother or sister here is the answer

•\huge\bigstar{\underline{{\red{A}{\pink{n}{\color{blue}{s}{\color{gold}{w}{\color{aqua}{e}{\color{lime}{r}}}}}}}}}\huge\bigstar•

6Nm is the answer

Explanation:

15N×0.4m= 6Nm

hope it helps you

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