a force of 15N pulls the 10kg block for 2m.find the work done by friction on 5kg block that is above the 10kg block if u=0.5
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We know that maximum friction is given by F=μ×N.
According to the given data, we have,
N=5×g=50
maximum friction force=μN=.5×50=25 Newton
Given friction force is 20 Newton which is less than maximum friction force.
Therefore it's static case which means both of them will move together.
Acceleration of 10 kg Block is given by,
a=
M
f
=20/10
a=2 m/s
2
Now applying newton's second law on 5 kg block will give,
F−20=ma
F=30 newton
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