Question

A force of 1800N is acting on the surface area of 0.06m'. The pressure
exerted by the force will be:
a. 3 kPa
c. 300 kPa
b. 30 kPa
d. 3000 kPa​

Answer 1

Answer :

Option C (30 kPa)

________________

As per the provided information in the given question, we have :

• Force acting (F) = 1800 N
• Surface area (A) = 0.06 m²

We are asked to calculate the pressure exerted (P).

Let's first understand about pressure. Pressure is defined as force per unit area. Its SI unit is Pa. Pa is also Pascal. When there is less area, there is more pressure. When there is more area, there is more pressure.

Now, coming back to question. As we know that,

$\longmapsto \bf { P = \dfrac{F}{A} }$

• P denotes pressure
• F denotes force
• A denotes area

$\longmapsto \rm { P = \dfrac{1800}{0.06} \; Pa }$

$\longmapsto \rm { P =\cancel{ \dfrac{180000}{6} } \; Pa }$

$\longmapsto \bf { P = 30000 \; Pa }$

Now, as we know that,

• 1 kPa = 1000 Pa, So,
• 30000 Pa = 30kPa

$\longmapsto \bf { P = 30 \; kPa }$

∴ The pressure exerted by the force will be 30 kPa.