Question

A force of 19.6 N when applied parallel to
the surface just moves a body of mass 10
kg kept on a horizontal surface. If a 5 kg
mass is kept on the first mass, the force
applied (in newton) parallel to the surface to
just move the combined body is​

Answer 1

Answer:

since with F=19.6N

10 kg block just moves

so friction F=19.6N

f=19.6-mu(mg)=mu(10)(g)

u=19.6/10

F'=f'=mu×N=mu(5+10)(g)

F'=19.6/10g(15g)

so, F'=19.6×15/10=29.4N