Question

A force of 2.5N is experienced by a point of charge of 5*10^-6C at a point in an electric field . The potential gradient at that point in SI unit is ?​

Answer 1

Answer:

The potential gradient at the position of charge is $E = 5 \times 10^5 N/C$

Explanation:

As we know that the the force on a point charge in external electric field is given as

$F = QE$

here we know that

Q = charge of the particle

E = Electric field intensity

now we know that

$Q = 5 \times 10^{-6} C$

$F = 2.5 N$

now from above formula we have

$2.5 = (5 \times 10^{-6})E$

$E = 0.5 \times 10^6 N/C$

#Learn

Topic : Force of electric charge

https://brainly.in/question/4412031

Answer 2

Answer:

5* 10^-6

Explanation:

The potential gradient at the position of charge is E = 5 \times 10^5 N/CE=5×10

5

N/C

Explanation:

As we know that the the force on a point charge in external electric field is given as

F = QEF=QE

here we know that

Q = charge of the particle

E = Electric field intensity

now we know that

Q = 5 \times 10^{-6} CQ=5×10

−6

C

F = 2.5 NF=2.5N

now from above formula we have

2.5 = (5 \times 10^{-6})E2.5=(5×10

−6

)E

E = 0.5 \times 10^6 N/CE=0.5×10

^6

N/C