A force of 2 gf produces a moment of force of 0.75 Nm . Find the perpendicular distance between the point of application of force and turning point
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Answer: 37500 cm (375m)
Explanation:
*Coversion of Force: 2gf = 0.002kgf
*Moment of force = Force x Perpendicular distance(r)
-> 0.75 = 0.002 * r
-> r= 0.75/0.002 = 375m = 37500cm
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