Question

A force of 2 N acts on a body of mass 10 kg for 1 minute the change in velocity of the body will be​

Answer 1

Given :

• Force acting on the body, F = 2 N
• Mass of body, m = 10 kg
• Time for which force acts, t = 1 min = 60 sec

To find :

• Change in velocity, Δ v = final velocity - initial velocity = v - u =?

Formula required :

• Expression of Newton's second law

     F = m a

• First equation of motion

    v = u + a t

[ Where F is force, m is mass, a is acceleration, v is final velocity, u is initial velocity and t is time ]

Solution :

By Newton's second Law of motion

→ F = m a

→ 2 = 10 × a

→ a = 2 /10

→ a = 0.2 m/s²

Now,

Using first equation of motion

→ v = u + a t

→ v - u = a t

→ Δ v = a t

→ Δ v = 0.2 × 60

→ Δ v = 12 m/s

Therefore,

• Change in velocity would be 12 m/s.

Answer 2

Explanation :-

Given :-

• Force (F) = 2N
• Mass(m) = 10kg
• Time (t) = 1min ↪60sec

To Find :-

• The change in velocity of the body.

Solution :-

As we know that,

Force (F) = Mass(m) × Acceleration (a)

[ Putting values ]

↪ 2 = 10 × a

↪ a = 2/10

↪ $\bold{a = 0.2\:m/s^2}$

Applying 1st equation of motion,

Final velocity (v) = Initial velocity (u) + Acceleration (a) × Time(t)

↪ v - u = at

↪ Δv = at

↪ Δv = 0.2 × 60

↪$\bold{Δv = 12\:m/s}$

Hence,

• The change in velocity of the body is 12 m/s.