Question

A force of 20 N acts on 16 kg block kept on a smooth horizontal surface for 6 seconds and then removed. find the distance covered by it in 10 s

Answer 1

Here is your required ans

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Answer 2

here F=ma

20=16a

a=5/4m/sec^2

u=0 t=6sec

S= ut+1/2 at^2

S= 0+1/2×5/4×6×6

S= 45/2m

from here v=15/2m/sec

this v is initial for next 4 secs then

u=15/2   t=4sec

S= 15/2×4= 30m

total distance = 30+45/2=105/2m