Question

a force of 20 N acts on a body.if the displacement of the body is 0.5m in the direction opposite to the of the force,calculate the work done by the force ​

Answer 1

Answer:

Explanation:

We have given that , the force will be = 20N.

and,

Displacement of the body = 0.5m with in opposite direction of force.

We conclude work done by force?

We know ,

W = f.d cosα

let cosα=180°.

⇒cosα=1.

W=20*0.5*1.

W=10.

Now, work done =10Nm.

Answer 2

Answer:

A force of 20 N acts on a body.if the displacement of the body is 0.5m in the direction opposite to the of the force, The work done by the force ​will be $10\ J$

Explanation:

Let  F be the force applied to an object and s be the distance moved by that object by the application of this force.

The work done (W) on the body will be the energy converted or transferred through this process.

The work done can be obtained by the product of force and displacement.  

That is,

$W = F\times s$    ...(1)

Given,

$F = 20\ N$

$s = 0.5\ m$

Substituting these values into equation (1),

$W = 20\times 0.5 = 10 J$

The work done by the force = $10\ J$