Question

A force of 20 N acts on a body of mass 5 kg for 4 second initially at rest. Calculate:
I) the velocity acquired by the body. II) change in momentum of the body.​

Answer 1

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A force of 10N acts on a body of mass 2kg for 3s, initially at rest. Calculate: (i) the velocity acquired by the body, and (ii) change in momentum of the body.

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ANSWER

F=10N,m=2kg,Δt=3s,u=0

(i) F=ma

Putting the values, 10N=2kg×(a)

Therefore, acceleration, a=5m/s

2

Acceleration, a=

Δt

Δv

Change in velocity, Δv=a×Δt=5m/s

2

×3s=15m/s

v−u=15m/s

Therefore, velocity acquired by the body, v=15m/s

(ii) Force can be also written as, F=

Δt

Δp

Where, p is momentum.

Therefore, change in momentum, Δp=F×Δt=10N×3s=30kgm/s