Question

A force of 20 N acts on a particle and displaces it through 4 m at an angle 30' with it. The work done by the
force is​

Answer 1

Answer:W = 40$\sqrt{3$

Explanation:

work done = F *d *cos theta

W = 20 * 4 * $\sqrt{3$/2

W = 40$\sqrt{3$