Question

A force of 20 N is acting along a line having slope 3/4 , Calculate Resultant​

Answer 1

Answer:

6h3th3yht3h3tb

Explanation:

y3tb3tg2tht3b3yb

Answer 2

Explanation:

Let the other Force be of magnitude x and the angle it makes with resultant be θ.

Now, the components of the two vectors along the resultant should be of magnitude of the resultant and the component of these two vectors resolved in the direction perpendicular to resultant should be zero.

In other words, 20

3

cos30

0

+xcosθ=20

which gives, 20

3

.

2

3

+xcosθ=20

or, 30+xcosθ=20, giving xcosθ=−10 --- (1)

Now, resolving in the perpendicular direction, 20

3

.sin30

0

+xsinθ=0

or, 10

3

+xsinθ=0, giving xsinθ=−10

3

--- (2)

Squaring and adding (1) and (2), we get:

(xcosθ)

2

+(xsinθ)

2

=x

2

=100+300=400 , thus x=20 N