A force of 20 N is acting on a block of mass 2 kg horizontally. The coefficient of friction between the block and the surface is 0.1. What will be the acceleration of the block (g = 10 m/s²)
Options
10 m/s²
2 9 m/s²
2 1 m/s²
2 m/s²
Answers
Answered by
0
Explanation:
18.0 N
Max. frictional force
f
max
=μN
=μ(mg+Fsin53
0
)
=0.2(20×10+30
5
4
)=44.8N
As Fcosθ=30cos53
0
=30×
5
3
=18N<f
max
friction force will also be 18 N. solution
Answered by
0
Answer:
I don't know
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