Question

a force of 20 n is applied on both the boxes kept on the table​

Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

Given :    m=3kg                      F=20 N

Frictional force        f=5  N

Thus acceleration of the box    $a= \frac{F-f}{m} =\frac{20-5}{3} =5 m/s^{2}$