A force of 20 N is applied on the object of mass 200gram at the rest for 6 sec only . How much velocity the object will acheive
Answers
Answer:
The velocity the object will achieve is 600 m/s.
Step-by-step explanation:
Given :
A force of 20 N is applied on the object of mass 200 gram at the rest for 6 sec only.
To find :
the velocity the object will achieve
Solution :
Force, F = 20 N
mass, m = 200 g = 200/1000 = 0.2 kg
time taken, t = 6 sec
initial velocity, u = 0 m/s
final velocity, v = ?
We know,
F = ma
The acceleration is the rate of change of velocity.
a = (v – u)/t
Substituting the values,
20 = 0.2 × (v – 0)/6
20 = 0.2 × v/6
20 × 6 = 0.2v
120 = 0.2v
v = 120/0.2
v = 600 m/s
Therefore, the velocity the object will achieve is 600 m/s.
Answer:
The velocity the object will achieve is 600 m/s.
Step-by-step explanation:
Given :
A force of 20 N is applied on the object of mass 200 gram at the rest for 6 sec only.
To find :
the velocity the object will achieve
Solution :
Force, F = 20 N
mass, m = 200 g = 200/1000 = 0.2 kg
time taken, t = 6 sec
initial velocity, u = 0 m/s
final velocity, v = ?
We know,
F = ma
The acceleration is the rate of change of velocity.
a = (v – u)/t
Substituting the values,
20 = 0.2 × (v – 0)/6
20 = 0.2 × v/6
20 × 6 = 0.2v
120 = 0.2v
v = 120/0.2
v = 600 m/s
Therefore, the velocity the object will achieve is 600 m/s.