A force of 20 N is required to pull a body of mass 5 kg through an inclined plane making an angle of 30° with the horizontal. Find the work done against the force of friction between the body and the inclined plane.
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Answer:
Correct option is D)
From FBD of block
N=mgcosθ
and
mgsinθ=F+f
F=mgsinθ−f
F=50×1/2−0.5×50×0.866
F=25−21.65
F=3.35N
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Solve any question of Laws of Motion with
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Answer:
Hii mate
Explanation:
F= 20N
M= 5 KG
G= 9.8 m/s square
S= 5m
W= F×S
W= 20n×5m 100J
F= m g
F= 2×9.8=19.6N
W= 19.6×5×cos 30°
W= 49J
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