Question

a force of 20 Newton acts on a body of mass 4 kg at rest for 10 seconds calculate the velocity acquired and the distance travelled by the body during the interval

Answer 1

250 m

please mark me as brainliest

Explanation:

Force=20N

mass=4kg

by netwon's second law of motion,

f=ma

20=4a

a=20÷4=5m/sec^2

initial velocity(u)=0 (object was at rest)

time=10sec

since final velocity(v) = u + at

v= 0+ 5×10

v=50m/sec

by v^2 =u^2 + 2as

50^2 = 0^2 + (2×5×s)

2500 =10s

s=2500÷10=250m

hnece distance travelled=250m