A force of 20 newton apply on an area of 0.2mmsq..find the pressure devolp at pascal
Answers
Answered by
1
Force = 20 N
Area = 0.2 mm^2
1m^2 = (1000)^2 mm^2 = 10^6 mm^2
1mm^2 = 1/10^6 = 10^(-6) m^2
Area = 0.2 mm^2 = 2×10^(-7) m^2
Pressure = F/A = 20/2×10^(-7) = 10^8 Pa
Pressure acting on the surface is 10^8 Pascal.
Area = 0.2 mm^2
1m^2 = (1000)^2 mm^2 = 10^6 mm^2
1mm^2 = 1/10^6 = 10^(-6) m^2
Area = 0.2 mm^2 = 2×10^(-7) m^2
Pressure = F/A = 20/2×10^(-7) = 10^8 Pa
Pressure acting on the surface is 10^8 Pascal.
Similar questions