Question

A force of 20 newton is applied on a body of mass 5 kg resting on a horizontal plane the body can gain kinetic energy of 10 joule after its moves a distance 2 metre. The frictional force is

Answer 1

M=5 Kg , P(applied force)=20 N K.E=10 joule s=2 m here u=0 so v^2=2as

KE=1/2mv^2

Or 10= 1/2m(2as)

Or 10= mas

Or 10= 5.a.2

Or 10= 10.a

Or a= 1 m/s^2

We know a=(P-F)/m

Or 1=(20-F)/5

Or 5=20-F

Or F =15 N

Answer 2

Explanation:

frictional force = 15N

Hope it is useful for you

mark me as brainlist