Question

A force of 200 N acts 40 degrees to the spoke of a cycle wheel 250 mm in radius. The moment about the center of the wheel will be nearer to_________ N.m.

Answer 1

Answer:

answer is 32 nm

Explanation:

prove in attachment ☝️

Answer 2

Answer:

The correct answer is equal to 32.13Nm.

Explanation:

Given:

R = 1/4m

F = 200N

Ф = 40°

Here,

The distance from the center to the point where the force act is denoted by R.

The force is denoted by F.

The angle is denoted by Ф.

Now,

By the equation,

Moment about the center of the wheel $= RFsin$Ф

Moment about the center of the wheel $= \frac{1}{4}\times 200 \times sin$40°

Moment about the center of the wheel $= \frac{1}{4}\times 200 \times 0.64$

Moment about the center of the wheel  = 32.13Nm

So, the moment about the center of the wheel will be nearer to 32.13Nm.