Question

A force of 200 Newton acts between two objects at a certain distance apart.what is the value of the Force when the distance is halved?

Answer 1

Answer:

800N

Explanation:

let the masses of the two objects be M1 and M2

and their distance apart = r

Therefore the force acting F1 = GM1M2r2

for a new distance of r/2, we have a force of

F2 = GM2M2r/2

Thus F1×r2=GM1M1andF2×(r/2)2=GM1M1

Since GM1M1=GM1M1⟹F1×r2=F2×(r/2)2

Therefore 200×r2=F2×r2/4F2=4×200×r2r2=800N

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Answer 2

Explanation

let the masses of the two objects be M1 and M2

and their distance apart = r

Therefore the force acting F1 = GM1M2/r2

for a new distance of r/2, we have a force of

F2 = GM2M2r/2

F2 = GM2M2r/2Thus F1×r2=GM1M1andF2×(r/2)2=GM1M1Since GM1M1=GM1M1⟹F1×r2=F2×(r/2)2Therefore 200×r2=F2×r2/4F2=4×200×r2r2=800N